If you’re struggling with this week’s questions, this walkthrough should help you get the skills you need. This week, we’re exploring: Question 1: Dividing Fractions The key to dividing fractions is using the inverses. We use the inverse operation (we multiply instead of divide) with the inverse (reciprocal) fraction. This is often remembered as ‘Keep Change Flip’: keep the first fraction, change the operation to multiply and flip the last fraction. Let’s calculate \(1\frac{7}{8} \div 2\frac{3}{5}\). We start by writing the mixed numbers as improper fractions. To do this, multiply the whole number by the denominator and then add the numerator. … Continue reading Daily Maths Revision – Week 16 Walkthrough

If you’re struggling with this week’s questions, this walkthrough should help you get the skills you need. If it’s a formula you need, here are the ones that are relevant this week. Quadratic Formula\(x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\) The Cosine Rule\(a^2=b^2+c^2-2bc\cos A\) This week, we’re exploring: Question 1: Solving Quadratic Equations Using the Formula When we can’t solve a quadratic equation using factorising, we can use the formula. For the formula to work, we need to have the equation in the form \(ax^2+bc+c=0\). \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] Find the exact solutions to \(3x^2-4x=2\). First, we need to rearrange the formula so it’s equal to 0. We do … Continue reading Daily Maths Revision – Week 15 Walkthrough

If you’re struggling with this week’s questions, this walkthrough should help you get the skills you need. If it’s a formula you need, here is the one that is relevant this week. Area of a TrapeziumArea = \(\frac{1}{2}(a + b)h\) This week, we’re exploring: Question 1: Bound Calculations Error intervals are essentially an inequality showing the values that a rounded number could take. Bound calculations use the maximum and minimum values that rounded numbers could take to find the maximum or minimum value that a calculation could take. A number, \(x\), is rounded to 1 decimal place. The result is … Continue reading Daily Maths Revision – Week 14 Walkthrough

If you’re struggling with this week’s questions, this walkthrough should help you get the skills you need. This week, we’re exploring: Question 1: Solving Quadratics by Factorising Factorising is one way to solve quadratic equations. It doesn’t work for all quadratics but, if the question is on a non-calculator paper, the chances are you can solve the quadratic by factorising it. Solve \(6x^2 – 19x + 15 = 0\).  First, we factorise the left-hand side. You may want to look back at week 5 if you think you need to revisit this. To factorise, we look for a pair of … Continue reading Daily Maths Revision – Week 13 Walkthrough

If it’s a formula you need, here are the ones that are relevant this week. You are given the trigonometric ratios in the 2023 exams but it’s in a different format than your used to so it may be worth memorising them anyway. Trigonometry Ratios\(\sin \theta = \frac{O}{H} \)\(\cos \theta = \frac{A}{H} \)   \(\tan \theta = \frac{O}{A} \)   This week, we’re exploring: Question 1: Converting Ratios to Fractions This topic is one that is answered incorrectly surprisingly often. The key is to remember that the denominator of the fraction is the total number of parts in the ratio. For example, if … Continue reading Daily Maths Revision – Week 12 Walkthrough

This week, we’re exploring: Question 1: Cones You are given the formula for both the curved surface area and volume of a cone. So, finding these values is mostly about substitution. Just make sure you are using the radius for \(r\), the slant height for \(l\) and the perpendicular height for \(h\). \(\text{volume} = \frac{1}{3}\pi r^2h \)\(\text{curved surface area} = \pi rl \) Let’s find the volume and total surface area of this cone. We will give both answers in terms of . The slant height is 13cm and the perpendicular height is 12cm. 10cm is the diameter but we … Continue reading Daily Maths Revision – Week 11 Walkthrough